Question

write the zeros of the polynomial x2-3x-4

Answer 1

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➡️x^2 - 3x - 4
=> x^2 - 4x+x - 4
=>x(x - 4) + 1 (x-4)
=> (x-4 ) (x+1)

So , Zeroes of the polynomial are 4 & -1✔
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Answer 2

$x = ({b}^{2} - + \sqrt{ d} ) \div 2a ...x = (9 - + \sqrt{25} ) \div 2......x = (9 - + 5) \div 2....x = 2 or.7....$
where d=d^2-4ac