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Hey mate !!!!!
Here's your answer »»»»»»»»»»
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Let the length of the plot be 11x
And the breadth of the plot be 4x
Cost of fencing the rectangular plot =
Rupees 100 per m is Rupees 15000
Hence per 1 rupee, cost will be Rupees 150
As we know that 1 multiplied by any number is the number itself, we have the perimeter of the rectangular plot as 150m
We know that perimeter of a rectangle =
2(l × b)
→2(11x + 4x) = 150m
→11x + 4x = 75m
→15x = 75m
→x = 5
Therefore, the length of the plot = 11x
= 11 × 5
= 55m
And the breadth of the plot = 4x
= 4 × 5
= 20m
••••••••••••••••••••••••••••••••••••••••••••••••••
You may also refer the attachment
Hope this helps
@PoojaBBSR
Here's your answer »»»»»»»»»»
••••••••••••••••••••••••••••••••••••••••••••••••••
↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓
Let the length of the plot be 11x
And the breadth of the plot be 4x
Cost of fencing the rectangular plot =
Rupees 100 per m is Rupees 15000
Hence per 1 rupee, cost will be Rupees 150
As we know that 1 multiplied by any number is the number itself, we have the perimeter of the rectangular plot as 150m
We know that perimeter of a rectangle =
2(l × b)
→2(11x + 4x) = 150m
→11x + 4x = 75m
→15x = 75m
→x = 5
Therefore, the length of the plot = 11x
= 11 × 5
= 55m
And the breadth of the plot = 4x
= 4 × 5
= 20m
••••••••••••••••••••••••••••••••••••••••••••••••••
You may also refer the attachment
Hope this helps
@PoojaBBSR
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