write this in java (blueJ)
no spam
Answers
Solution 1:
public class Greatest{
public static void main(int a, int b, int c){
int max=Math.max(a,Math.max(b,c));
System.out.println("Largest number is: "+max);
}
}
Logic is very simple. Accept three numbers. Compare the first number with the maximum of second and third number using max() function to get the highest value.
Solution 2:
import java.util.Scanner;
public class Grade{
public static void main(String s[]){
Scanner sc=new Scanner(System.in);
System.out.print("Enter your marks: ");
double marks=sc.nextDouble();
sc.close();
if(marks<0 || marks>100)
System.out.println("Invalid Marks.");
else{
if(marks>=80)
System.out.println("Grade: A");
else if(marks>=50)
System.out.println("Grade: B");
else
System.out.println("Grade: C");
}
}
}
Check the conditions given using if else statements. If conditions become true, display the respective grade.
Solution 3:
import java.util.Scanner;
public class Calculator{
public static void main(String s[]){
int a,b,result;
Scanner sc=new Scanner(System.in);
System.out.print("Enter first number: ");
a=sc.nextInt();
System.out.print("Enter second number: ");
b=sc.nextInt();
System.out.println("\n1. Addition.");
System.out.println("2. Subtraction.");
System.out.println("3. Multiplication.");
System.out.println("4. Division.");
System.out.println("5. Modulo Operation.");
System.out.print("\nEnter your choice: ");
switch(sc.nextInt()){
case 1:
result=a+b;
System.out.println("Sum = "+result);
break;
case 2:
result=a-b;
System.out.println("Difference = "+result);
break;
case 3:
result=a*b;
System.out.println("Product = "+result);
break;
case 4:
result=a/b;
System.out.println("Quotient = "+result);
break;
case 5:
result=a%b;
System.out.println("Remainder = "+result);
break;
default:
System.out.println("Invalid Choice.");
}
sc.close();
}
}
Accept two numbers, request the user to enter a valid number and perform the respective operator from the list of choices using switch-case statement.
Refer to the attachments for output.
