Question

write this in standard form 5m^3-6m+7​

Answer 1

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$\: \: \orange{ \bold{ \underline{ \underline{step \: by \: step \: explaination}}}}$

$\: \: \bigstar\displaystyle \sf{y = -1 \: \: ......given}$

$\: \: \mapsto \bf{q(y) = 4 {y}^{3} + k {y}^{2} - y - 1}$

$\: \\ \mapsto \bf{q(y) = 4 {( - 1)}^{3} + k {( - 1)}^{2} - ( - 1) - 1}$

$\: \: \mapsto \bf{q(y) = - 4 + k + 2 - 1}$

$\: \mapsto \bf{q(y) = - 4 + k + 1}$

$\: \: \mapsto \bf{ 0 = - 4 + k + 1}$

$\: \: \mapsto \bf{0 = - 3 + k}$

$\: \: \mapsto \bf{k = 3}$

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x+2=0

x=-2

=x³-2mx²+16

=(-2)³-2m(-2)²+16

=-8-2m+16=0

=-2m+8=0

=-2m=-8

=m=4