write three consecutive number of 1257
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What three consecutive integers have a sum of 1257?
Here we will use algebra to find three consecutive integers whose sum is 1257.
We assign X to the first integer. Since they are consecutive, it means that the 2nd number will be X+1 and the third number will be X+2 and they should all add up to 1257. Therefore, you can write the equation as follows:
X + X + 1 + X + 2 = 1257
To solve for X, you first add the integers together and the X variables together. Then you subtract 3 from each side, followed by dividing by 3 on each side. Here is the work to show our math:
X + X + 1 + X + 2 = 1257
3X + 3 = 1257
3X + 3 - 3 = 1257 - 3
3X = 1254
3X/3 = 1254/3
X = 418
Which means that the first number is 418, the second number is 418+1 and third number is 418+2. Therefore, three consecutive integers that add up to 1257 are:
418
419
420
Since, 418 + 419 + 420 = 1257, it confirms that the answer above is correct.
What three consecutive integers have a sum of 1258?
Here is the next algebra problem we solved.
Answer:
x+x+1+x+2=1257
3x=1254
x=418
ans:418,419,420