Science, asked by yatin283, 11 months ago

Write word equations and then balanced equations for the reaction taking place when -
(a) dilute sulphuric acid reacts with zinc granules.
(b) dilute hydrochloric acid reacts with magnesium ribbon.
(c) dilute sulphuric acid reacts with aluminium powder.
(d) dilute hydrochloric acid reacts with iron filings.

Answers

Answered by Arslankincsem
37

Answer:


The answer to the option i) is H2SO4 + Zn = ZnSO4 + H2 (gas).


The answer to option ii) is 2Hcl + Mg = MgCl2 + H2 (gas).


The answer to option iii) is 3H2SO4 + 2Al = Al2 (SO) 4 + 3H2 (gas).


The answer to the iv) option is 6HCL + 2FeCl3 + 3H2 (gas).

Answered by Anonymous
59

(a) dilute sulphuric acid reacts with zinc granules:

\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>\</strong><strong>b</strong><strong>f</strong><strong>\pink{</strong><strong>dilute sulphuric acid + zinc → Zinc Sulphate + Hydrogen Gas</strong><strong>}

\small\</strong><strong>b</strong><strong>f</strong><strong>\pink{</strong><strong>H2SO4(aq) + Zn → ZnSO4(aq) + H2(g)</strong><strong>}

(b) dilute hydrochloric acid reacts with magnesium ribbon:

\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>\bf\pink{</strong><strong>dilute Hydrochloric + Magnesium → Magnesium Chloride + Hydrogen Gas</strong><strong>}

\</strong><strong>s</strong><strong>m</strong><strong>a</strong><strong>l</strong><strong>l</strong><strong>\bf\pink{</strong><strong>2HCl(aq) + Mg → MgCl2(aq) + H2(g)</strong><strong>}

(c) dilute sulphuric acid reacts with aluminium powder:

\small\bf\pink{</strong><strong>dilute Sulphuric Acid + Aluminium → Aluminium Sulphate + Hydrogen Gas</strong><strong>}

\small\bf\pink{</strong><strong>3H2SO4(aq) + 2Al(s) → Al2(SO4)3(aq) + 3H2(g)</strong><strong>}

(d) dilute hydrochloric acid reacts with iron filings:

\small\bf\pink{</strong><strong>dilute Hydrochloric Acid + Iron → Ferrous Chloride + Hydrogen Gas</strong><strong>}

\small\bf\pink{</strong><strong>6HCl(aq) + 3Fe(s) → 3FeCl2(aq) + 3H2(g)</strong><strong>}

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