Question

write your observation and chemical equations for the following
1) what happens when ferrous sulphate is heated
2) what happens when silver bromide exposed to sunlight
3) what happens when copper is heated in presence of oxygen

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Answer 1

1) in image

2) The silver bromide crystals are light sensitive upon exposure to light, the silver bromide crystals are altered to form a latest image .The electrons then reduces the Ag+ to Ag0.

3) in 2nd image

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Answer 2

Answer:

Answer:-⤵️⤵️

1.On heating, ferrous sulphate crystals lose water and anhydrous ferrous sulphate (FeSO4) is formed. So their colour changes from light green to white. On further heating, anhydrous ferrous sulphate decomposes to form ferric oxide (Fe2O3), sulphur dioxide (SO2) and sulphur trioxide (SO3).

Reaction:-

$2Feso_{4}(s)→Fe_{2}O_{3}(s)+So_{2}(g)+So_{3}(g)$

2.Silver bromide is a photosensitive compound that decomposes when exposes to sunlight. That is the reason it is always kept in the dark bottles. The reaction of silver chloride with sunlight is also called as photolytic decomposition reaction in which the decomposition reaction carried out by sunlight.

The balance chemical reactions can be written as:

$2AgBr \frac{sunlight} → 2Ag+Br_2$

This is one of the most important reaction used in photography (mainly in black and white photography).

3.The copper metal turns black when it is heated in the burner.

When the metal is placed in the H2 atmosphere inside the funnel, it returns to the original copper color.

When the funnel is removed, the copper turns black again.

Explanations (including important chemical equations):

$2 Cu (s) + O_2 (g) → 2 CuO (s) \\ \\ CuO (s) + H_2 (g) →Cu (s) + H_{2}O (g)$

Heated copper metal reacts with oxygen to form the black copper

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