Question

Wu
12. Divide 42 into two parts such that one-third of one part is equal to one-fourth of the other
Part. Find the two numbers.​

Answer 1

let x and y be the 2 numbers

x + y = 42..................eq(1)

and

$= > \frac{1}{3} x = \frac{1}{4} y \\ = > 4x = 3y \\ = > x = \frac{3}{4} y \\ putting \: te \: value \: of \: x \: in \: eq(1) \\ = > \frac{3}{4} y + y = 42 \\ = > \frac{7y}{4} = 42 \\ = > 7y = 168 \\ = > y = 24 \\ \\now \: x = \frac{3}{4} \times 24 = > 18$

the required no.s are 18 and 24