Question

x=0,y=1 1.3x²+y².2.x²-y².3.x²+xy+y²​

Answer 1

Answer:

y=1 1.3x²+y².2.x²-y².3.x²+xy+y²​

putting x=0 (Given)

y=0+y².0-y².0+0+y²​

so,

y = y²​

y²​-y=0

hence, b²-4ac =1

discriminant(d)> 0

y= (-1 + 1)/2 or (-1 - 1)/2

y= 0 or -1