( x -1)² - 5(x-1) -6 = 0
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Answered by
5
Let, x-1 = t
Then, according to the question :
t² - 5t - 6
=> t²-6t+t-6 = 0
=> t(t-6)+1(t-6) = 0
=> (t-6)(t+1) = 0
t = 6 and -1
When t = 6 then, x = 6+1 = 7
when t = -1 then, x = -1+1 = 0
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Answered by
1
Answer:
7,0
Step-by-step explanation:
let x-1 = a
a²-5a-6=0
a²-6a+a-6=0
(a-6)(a+1)=0
solving
a=6, -1
if a=6, x=6+1=7
if a=-1, x=-1+1=0
therefore, x=7,0
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