Question

(x+1)^2-x^2=0 has how many real roots
Fast guys

Answer 1

Answer:

$\huge\purple {\mathfrak{Bonjour Mate!}}$

(x^2+1)^2-x^2=0

(x^2+1)^2=x^2

rooting on both sides

we get

x^2+1=x x^2+1=-x

x^2-x+1=0 x^2+x+1=0

det of equations is less than zero

hence they have imaginary roots

Answer 2

Step-by-step explanation:

no real roots

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