Question

(x+1)^2 + x - 5 miscellaneous factorization ​

Answer 1

Answer:

please Mark as brilliant answer

Answer 2

Question -

Factorise -

( x + 1 ) ² + x - 5

Solution -

$\sf{ \bold{ Factorise \: - }} \\ \\ \sf{ \implies { ( x + 1 ) ^ 2 + x - 5 }} \\ \\ \sf{ \implies { x^2 + 2x + 1 + x - 5 }} \\ \\ \sf{ \implies { x^2 + 3x - 4 }} \\ \\ \sf{ \implies { x^2 + 4x - x - 4 }} \\ \\ \sf{ \implies { x ( x + 4 ) - 1 ( x + 4 ) }} \\ \\ \sf{ \implies { ( x - 1 )( x + 4 ) }} \\ \\ \sf{ \bold { Hence \: Factorised }}$

Hence , the required factorisation is ( x - 1 )( x + 4 ) .

____________