(x + 1) (2x - 1) (x + 3)
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Lets attempt this question in a peculiar way!
(x+1)(2x−1)(x+3)
=((x+1)(2x−1))(x+3) .............multiplying (x+1) and (2x-1) first.
=((x+1)(2x−1))(x)+((x+1)(2x−1))(3) .........Using distributive property.
=2x3+x2−x+6x2+3x−3 ...........Opening the brackets and simplifying.
=2x3+7x2+2x−3
HOPE THIS HELPS :D
Answered by
1
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