Question

(x+1)(2x+1)=(x+3)(2x+3)-14 plzz answer me fast​

Answer 1

Answer:

$(x + 1)(2x + 1) = (x + 3)(2x + 3) - 14 \\ \\ x(2x + 1) + 1(2x + 1) = x(2x + 3) + 3(2x + 3) - 14 \\ \\ 2 {x}^{2} + x + 2x + 1 = 2 {x}^{2} + 3x + 6x + 9 - 14 \\ \\ 3x + 1 = 9x - 14 \\ \\ 1 + 14 = 9x - 3x \\ \\ 15 = 6x \\ \\ x = \frac{15}{6}$

Answer 2

Hey friend,

Here is the solution :-

$(x + 1)(2x + 1) = (x + 3)(2x + 3) - 14 \\ \\ = > {2x}^{2} + 2x + x + 1 = {2x}^{2} + 6x + 3x + 9 - 14 \\ \\ = > {2x}^{2} + 3x + 1 = {2x}^{2} + 9x + 9 - 14 \\ \\ = > {2x}^{2} - {2x}^{2} + 3x - 9x = 9 - 14 - 1 \\ \\ = > - 6x = - 6 \\ \\ 6x = 6 \\ \\ x = \frac{6}{6} = 1 \\ \\ \\ therefore \: \: x = 1$

✨I hope this will help you....✨