Question

(x-1)^3+x^3+(x+1)^3=3x(x^2-1), then the value of x

Answer 1

1. Expand
x ^3 −2x ^2 +x−x ^2 +2x−1+x ^3 +x^ 3 +2x^ 2 +x+x^ 2 +2x+1=3x ^3 −3x

2. Simplify x ^3 −2x ^2 +x−x ^2 +2x−1+x ^3 +x^ 3 +2x^ 2 +x+x^ 2 +2x+1 to 3x^3+0+6x+0
3x ^3 +0+6x+0=3x ^3 −3x

3. Simplify 3x^3+0+6x+0 to 3x^3+0+6x
3x^3+0+6x=3x^3-3x

4. Simplify 3x^3+0+6x to 3x^3+6x
3x^3+6x=3x^3-3x

5. Cancel 3x^3 on both sides
6x= -3x

6. Divide both sides by -3
-2x=x

7.Subtract -2x from both sides
0=x+2x

8. Simplify x+2x to 3x
0=3x

9. Divide both sides by 3
0=x

10. Switch sides
x=0

DONE
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