Math, asked by anaysingh1415, 11 months ago

(x+1) (4x+2)+(x+1) (x+2)

Answers

Answered by saurabhkokare2212
0

Answer:

(x+1) (4x+2)=4x^2+6x+2

(x+1) (x+2)=x^2+3x+2

(4x^2+6x+2)- (x^2+3x+2)

3x^2+3x

3x(x+1)

x= -1, x=0

Answered by aniruddhaanturlikar
0

Answer:

Step-by-step explanation:

(x+1) (4x+2)+(x+1) (x+2)

0= (4x × x + 2 × x + 4x + 2) + (x² + 2 ×

x + x + 2)

0=(4x² + 2x + 4x + 2)+(x² + 2x + x + 2)

0= 4x² + 6x + 2 + x² + 3x + 2

0= 5x² + 9x + 4

0= 5x² + 5x + 4x + 4

0= 5x(x + 1) + 4(x + 1)

0= (5x + 4)(x + 1)

x = - 4/5,-1

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