(x+1) (4x+2)+(x+1) (x+2)
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Answer:
(x+1) (4x+2)=4x^2+6x+2
(x+1) (x+2)=x^2+3x+2
(4x^2+6x+2)- (x^2+3x+2)
3x^2+3x
3x(x+1)
x= -1, x=0
Answered by
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Answer:
Step-by-step explanation:
(x+1) (4x+2)+(x+1) (x+2)
0= (4x × x + 2 × x + 4x + 2) + (x² + 2 ×
x + x + 2)
0=(4x² + 2x + 4x + 2)+(x² + 2x + x + 2)
0= 4x² + 6x + 2 + x² + 3x + 2
0= 5x² + 9x + 4
0= 5x² + 5x + 4x + 4
0= 5x(x + 1) + 4(x + 1)
0= (5x + 4)(x + 1)
x = - 4/5,-1
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