Question

X + 1 by X - 1 + X - 2 by X +
$(x + 1) \div (x - 1) + (x + 2) \div (x - 2) = 4 \div 1 - (2x + 3) \div (x - 2)$
2 equals to 4 minus 2 X + 3 by X - 2​

Answer 1

Question :

$\frac{x + 1}{x - 1} + \frac{x + 2}{x - 2} = 4 - \frac{2x + 3}{x - 2}$

Solution :

First of all, simplify the expression :

$\frac{x + 1}{x - 1} + \frac{x + 2}{x - 2} + \frac{2x + 3}{x - 2} = 4$

$= > \frac{x + 1}{x - 1} + \frac{3x + 5}{x - 2} = 4$

$= > (x + 1)(x - 2) + (3x + 5)(x - 1) = 4(x - 2)(x - 1)$

$= > ( 4{x}^{2} + x- 7) = 4( {x}^{2} - 3x + 2) \\ \\ = > - 13x + 15 = 0 \\ \\ = > x = \frac{15}{13}$

Answer :

$x = \frac{15}{13}$