Question

‌கீ‌ழ்‌க்காணு‌ம் ப‌ல்லுறு‌ப்பு‌க் கோவைகளு‌க்கு (x -1) எ‌ன்பது கார‌ணியா எ‌ன‌க்கா‌ண்க
(i) x^3+5x^2-10x+4 ii)x^4+5x^2-5x+1

Answer 1

If the side of a square is tripled , how many times will its area be as compared to the area of the original square?

\Large\bold\star\underline{\underline\textbf{Formula\:used}}⋆Formulaused​​

→ Area of Square = ( side * side) = (side)² .

\Large\underline{\underline{\sf{Solution}:}}Solution:​​

Let us assume That, side of square is = a cm.

Than,

→ Area of square = (a)² = a² cm². --------- Equation (1)

Now,

Given That, side is Tripled , That means 3 Times ,

So,

→ New side of Square = 3 * a = 3a cm.

→ New Area of Square = (3a)² = 9a² cm² . ------ Equation(2)

Now, dividing Equation (2), with Equation (1) , we get,

→ ( New Area of Square) / ( Area of square) = 9a² / a²

→ ( New Area of Square) / ( Area of square) = 9/1

Hence, New area of square will be 9 Times The areaof Square .



\bf\red\bigstar\underline\textbf{\blue{Extra}\:Brainly\: \pink{Knowledge}}\red\bigstar★ExtraBrainly Knowledge​★

→The diagonals of a square bisect each other and meet at 90°.

→The diagonals of a square bisect its angles.

→Opposite sides of a square are both parallel and equal in length.

→All four angles of a square are equal.

→All four sides of a square are equal.

→The diagonals of a square are equal.

→ The perimeter of the square is given by :-

P = 4•Side.

→ The diagonal of a square is given by :-

D = √2•Side

→The area of a square is given by :-

A = (Side)²

→ The area of a square is also given by :-

A = (1/2)•(Diagonal)²



Answer 2

$(x-1)$ என்பது  ஒரு காரணி ஆகும்.

விளக்கம்:

(i) $x^3+5x^2-10x+4$

$p(x)=x^{3}+5 x^{2}-10 x+4$

$p(1)=I^{3}+5(1)^{2}-10(1)+4$

$=1+5-10+4$

$=10-10$

$=0$

$p(1)=0$

∴ $(x-1)$ என்பது $x^3+5x^2-10x+4$ என்ற பல்லுறுப்பு கோவையின் ஒரு காரணி ஆகும்.

(ii) $x^4+5x^2-5x+1$

$p(x)=x^{4}+0 x^{2}+5 x^{2}-5 x+1$

$p(I)=I^{4}+0 x^{3}+5(1)^{2}-5(1)+1$

= $1+0+5-5+1$

$= 1+1$

$p(1)= 2$

∴ $(x-1)$  என்பது $x^4+5x^2-5x+1$  என்ற பல்லுறுப்பு கோவையின் ஒரு காரணி ஆகும்.