Question

x-1 is a factor of kx^2-√2x+1 then k = ?​

Answer 1

Answer:

$x - 1 = 0$

$x = 1$

$k {x}^{2} - \sqrt{2} x + 1 = 0$

$k {(1)}^{2} - \sqrt{2} (1) + 1 = 0$

$k - \sqrt{2} + 1 = 0$

$k = \sqrt{2} - 1$

Answer 2

Answer:

√2-1

Step-by-step explanation:

x-1=0 ( as it is the factor)

x=1

Now substituting the value of x in

p(x)=kx²-√2x+1

=>k(1)²-√2(1)+1=0

=>k-√2+1=0

=>k+1=√2

=>k=√2-1

OR

=>k=-1+1.41

=>k=0.41

(You can use in point if u want but I prefer the answer in roots)

Hence, the value of k is √2-1

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