Math, asked by ujju6081, 1 year ago

(x+1) is a factor of p(x)=3x³+2x²+7x+8​

Answers

Answered by charu536
2

Answer:

x+1=0

x=-1

p(x) 3x^3+2x^2+7x+8

p(-1)=3(-1) ^3+2(-1) ^2+7(-1)+8

=-3+2-7+8=-10+10

=0 is your answer...

yes (x+1) is a factor of given polynomial.

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