(x+1) is a factor of p(x)=3x³+2x²+7x+8
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Answer:
x+1=0
x=-1
p(x) 3x^3+2x^2+7x+8
p(-1)=3(-1) ^3+2(-1) ^2+7(-1)+8
=-3+2-7+8=-10+10
=0 is your answer...
yes (x+1) is a factor of given polynomial.
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