Question

x + 1 is a factor of x^3+3x^2+3x+a , then a=?

Answer 1

Answer:

x^3+3x^2+3x+a =put x=-1. -1^3+3(-1)^2+3(-1)+a. -1+3-3+a. a=1

Answer 2

Answer:

a=1

Step-by-step explanation:

$p(x) = {x}^{3} + 3 {x}^{2} + 3x + a$

$g(x) = x + 1$

$putting \: g(x) \: = 0$

$x + 1 = 0$

$x = - 1$

$since \: g(x) \: is \: a \: factor \: of \: p(x) \: therefore \: when \: we \: will \: put \: value \: of \: x = - 1 \: in \: p(x) \: answr \: will \: be \: 0$

$0 = { - 1}^{3} + 3 \times ( { - 1}^{2} ) + 3( - 1) + a$

$0 = - 1 + 3 \times 1 - 3 + a$

$0 = - 1 + 3 - 3 + a$

$0 = - 1 + a$

$1 = a$