Math, asked by mehrishmirza06, 4 months ago

(x + 1) is a factor of x^3 + px^2 - 13x - 15. Find the value of p.

Answers

Answered by sahuananya34
1

Answer:

(x+1) =0

x= –1

p(x)= x^3+px^2–13x–15

p(-1)= (-1)^3+p(-1)^2-13(-1) -15

0= -1+p+13-15

0= p-16+13

-p= -3

p= 3

Answered by ACCIDENTALYgenius
1

Answer:

p = 3

Step-by-step explanation:

x= -1 ( given that x+1 is a factor, so x+1 = 0, x= -1 )

substitute the value of x in the given polynomial.

x^3 + px^2 - 13x - 15.

= (-1)^3 + p(-1)² - 13 * -1 -15 = 0

= -1 +p +13 -15 = 0

=-3 + p =0

therefore p= +3

Hope this helps:)

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