(x - 1) is a factor of (x³ - 1)
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Answered by
0
Answer:
yes your statement is correct
Answered by
0
Answer:
See the attachment
Step-by-step explanation:
p(x) = (x³ - 1)
p(1) = (1)^3 -1
= 1-1
= 0
(x - 1) is a factor of (x³ - 1)
Its true.
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