Question

x^1+logx=10x find the value of x in it
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Answer 1

(x)^1+logx =10x

Taking log on both side we have

=(1+logx) .logx = log10 + logx

=(1+ logx ) .logx = 1 + logx

=(1+logx) .logx - (1+logx) =  0

=(1+logx) (logx -1 ) = 0

Or 1+logx = 0

=logx = -1

Or x = 10-1 

And logx = 1

Or x = 10

Answer 2

$HEYA \: \\ \\ x {}^{(1 + log(x)) } = 10x \\ \\ taking \: log \: on \: both \: sides \: we \: have \: \\ \\ log(x {}^{(1 + log(x)) } ) = log(10 \times x) \\ \\ (1 + log(x) ) \times log(x) = log(10) + log(x) \\ becoz \: \: log(y {}^{n} ) = n log(y) \\ \\ (1 + log(x) ) \times log(x) = 1 + log(x) \\ becoz \: log(10) = 1 \\ \\ log(x) = 1 \\ \\ log(x) = log(10) \\ \\ x = 10$