Question

X - 1
quations by formula m
√2/² - 6f+ 3√2 = 0
avels a distance d = +2​

Answer 1

Step-by-step explanation:

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Answer 2

The correct option is A.

Given,

x=t

2

−4t+6

So, the change in velocity is:

dt

dx

=2t−4

Since velocity is changing,

At t=0,x

1

=6

At t=2,x

2

=2

So the magnitude of the distance traveled is:

6−2=4m

At t=3,x

3

=3

So distance traveled from t=2s to t=3s

x

3

−x

2

=3−2=1m

Thus the total distance is:

4+1=5m