Question

(x+1) square=2(x-3) check whether the following are quadratic equation( plzzzzzzzzzzzzzzzz batao)​

Answer 1

sorry I don't know what is the answer please follow me

Answer 2

Step-by-step explanation:

Given,

$({x+1})^{2}=2(x-3)$

we know that,

$\bold{\boxed{({a+b})^{2}={a}^{2}+{b}^{2}+2(a)(b)}}$

${x}^{2}+{1}^{2}+2(x)(1)=2(x-3)$

${x}^{2}+1+2(x)=2x-6$

${x}^{2}+1+2(x)-2(x)+6=0$

${x}^{2}+7=0$

therefore its a quadratic equation,since its degrees(highest power) is 2.

HOPE IT HELPS!