Question

x-1-(x - 1)2 + 4 - 4x(factorise)​

Answer 1

Answer:

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Step-by-step explanation:

x - 1 - (x-1)^2+4 - 4x

= x - 1 -(x^2–2x+1)+4–4x

= x - 1 - x^2 + 2x - 1 + 4 - 4x

= -x^2 - x + 2 = -(x^2 + x - 2)

= -(x^2 + 2x - x - 2)

= -{x(x+2) -1(x+2)}

= - (x+2)(x-1) = (x+2)(1-x)

Answer 2

Answer:

If  x - 1 - (x-1)^2+4 - 4x

= x - 1 -(x^2–2x+1)+4–4x

= x - 1 - x^2 + 2x - 1 + 4 - 4x

= -x^2 - x + 2 = -(x^2 + x - 2)

= -(x^2 + 2x - x - 2)

= -{x(x+2) -1(x+2)}

= - (x+2)(x-1)

= (x+2)(1-x)

or

If x - 1 - (x-1)2+4 - 4x  then

=  x - 1 -2x + 2 + 4–4x

= x - 1 - 2x + 2 + 4 - 4x

= -5x +5  

= -5(x-1)

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