Question

X-1/x+1=2x-5/3x-7 solve the equation

Answer 1

Hello mate.

Thanks for asking this question.

Your answer is =>

as we have given the equation =>

$=>\frac{(x-1) }{(x+1) }=\frac{(2x-5) }{(3x-7) }$

cross multiply both sides , we get =>

$=>(X-1) (3x-7) =(2x-5) (x+1)$

$=>3x^{2}-7x-3x+7\: =\: 2x^{2}-3x-12$

$=>3x^{2}-10x+7\: =\: 2x^{2}-3x-12$

$=>3x^{2}-2x^{2}-10x+3x+7+5=0$

$=>x^{2}-7x+12\:=\:0$

$=>x^{2}-3x-4x+12=0$

$=>x(x-3) \: -\:4(x-3) =\: 0$

$=>(x-3) (x-4) =0$

$=>(x-3) =0 \: \: \: \: or\: \: \: \: (x-4) =0$

$=>x\: =\: 3 \: \: \: or\: \: \: x\: =\: 4$

our factors for given equation are 3 & 4.

Answer 2

Answer:

Which is a solution of the equation (x-5)/5=(3x+7)/7 *