(x+1) (x+1) by suitable identity
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Answered by
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(a+b)²= a²+b²+2ab
let (x+1) be (a+b)
so (x+1)(x+1)=(x+1)²
x²+1+2*x*1=x²+1+2x
let (x+1) be (a+b)
so (x+1)(x+1)=(x+1)²
x²+1+2*x*1=x²+1+2x
Answered by
1
(a+b)²= a²+b²+2ab
let (x+1) be (a+b)
so (x+1)(x+1)=(x+1)²
x²+1+2*x*1=x²+1+2x
let (x+1) be (a+b)
so (x+1)(x+1)=(x+1)²
x²+1+2*x*1=x²+1+2x
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