Question

x-1/x+1-x+1/x-1=2/3(x≠+1),Examine whether the given equation are quadratic equations or not.

Answer 1

Answer :

Given that,

$\frac{x - 1}{x + 1} - \frac{x + 1}{x - 1} = \frac{2}{3} \\ \\ \implies \frac{ {(x - 1)}^{2} - {(x + 1)}^{2} }{(x + 1)(x - 1)} = \frac{2}{3} \\ \\ \implies \frac{ {x}^{2} - 2x + 1 - {x}^{2} - 2x - 1 }{ {x}^{2} - 1} = \frac{2}{3} \\ \\ \implies \frac{ - 4x}{ {x}^{2} - 1 } = \frac{2}{ 3} \\ \\ \implies2( {x}^{2} - 1) = 3( - 4x) \\ \\ \implies2 {x}^{2} - 2 = - 12x \\ \\ \implies {x}^{2} + 6x - 1 = 0$

The highest power of the variable "x" in the equation is 2. Thus the given equation is a quadratic one.

#MarkAsBrainliest