Question

(x+1)(x-1)(x²+1)
find the continued product

Answer 1

(x2-1)(x2+1)
(a+b)(a-b)=a2-b2
(x2)2-(1)2
x4-1
2 stands for square and 4 stands for square's whole square.
hope it helps.

Answer 2

Given expression,
  (x+1)*(x-1)*(x²+1)
=[(x+1)*(x-1)]*(x²+1)
Using formula (a=b)*(a-b)=a²-b²
Substituting x in place of a and 1 in place of b
Therefore,
  (x+1)*(x-1)=(x)²-(1)²
                   =x²-1
Therefore,
 [(x+1)*(x-1)]*(x²+1)=[x²-1]*(x²+1) 
=(x²-1)(x²+1)
Using formula (a=b)*(a-b)=a²-b²
Substituting x² in place of a and 1 in place of b,
Therefore,
  (x²-1)*(x²+1)=(x²)²-(1)²
                   =x⁴-1
    (Solved)