(x-1)(x-1)+(y-2)(y-2)+(z-3)(z-3)+(a-4)(a-4)=0 (x+y+z+a)=?
Answers
Answered by
1
Answer:
0
Step-by-step explanation:
(x-1)(x-1)+(y-2)(y-2)+(z-3)(z-3)+(a-4)(a-4)=0 (x+y+z+a)
0×anything = 0
so answer is 0
hope it helps
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