(x-1/x)^14 find independent term of x
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it's a binomial theorem ques.
((x-1)/x)^14
={1-(1/x)}^14
=14C0(1)^14(1/x)^0+14C1(1)^13(1/x)^1+.......14C14(1)^0(1/x)^14
Independent term is the first term in series
14C0(1)^14(1/x)^0
=14!/14!×0! ×1×1
=1
((x-1)/x)^14
={1-(1/x)}^14
=14C0(1)^14(1/x)^0+14C1(1)^13(1/x)^1+.......14C14(1)^0(1/x)^14
Independent term is the first term in series
14C0(1)^14(1/x)^0
=14!/14!×0! ×1×1
=1
Yes
Right
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