Math, asked by yashv3150, 1 year ago

x+1/x = 2+√3,Find the value of
x^2 +1/x ^2

Answers

Answered by LovelyG
3

Answer:

x +  \frac{1}{x}  = 2 +  \sqrt{3}  \\  \\ \sf squaring \: both \: sides -  \\  \\ (x +  \frac{1}{x} )^{2}  = (2 +  \sqrt{3} ) {}^{2}  \\  \\ x {}^{2}  +  \frac{1}{x {}^{2} }  + 2 = 2 {}^{2}  +  \sqrt{3} {}^{2} + 2 \times 2 \times  \sqrt{3}  \\  \\ x {}^{2}  +  \frac{1}{x {}^{2} } + 2 = 4 + 3 + 4 \sqrt{3}  \\  \\ x {}^{2}  +  \frac{1}{x {}^{2} } + 2 = 7 + 4 \sqrt{3}  \\  \\ x {}^{2}  +  \frac{1}{x {}^{2} } = 7 + 4 \sqrt{3}  - 2 \\  \\ x {}^{2}  +  \frac{1}{x {}^{2} } = 5 + 4 \sqrt{3}

Thanks!!

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