Math, asked by Shravsdlng9496, 9 months ago

(x+1) (x+2) /(x+11) (x-2) =1

Answers

Answered by ItzShinyQueen13
18

\bold\red{\mathcal{\underline{\underline{Answer:}}}}

6

\bold\red{\mathcal{\underline{\underline{Step-by-step\:Explaination:}}}}

  \frac{(x + 1)(x + 2)}{(x + 11)(x - 2)} = 1 \\ ⇒ \frac{ {x}^{2}  + 2x + x + 2}{ { {x}^{2}  - 2x + 11x - 22}}  = 1 \\ ⇒ \frac{ {x}^{2} + 3x + 2 }{ {x}^{2} + 9x - 22 }   = 1\\ ⇒ { {x}^{2} + 3x + 2}  =  {x}^{2} + 9x - 22 \\ ⇒ {x}^{2}   + 3x + 2 -  {x}^{2}  - 9x + 22 = 0 \\⇒ - 6x + 24 = 0 \\⇒ - 6x = -  24 \\ ⇒ x =  \frac{ - 24}{ - 6} \\ ⇒x =   4

\bold\green{\boxed{∴x=4}}

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Answered by minhaj66340
10

Answer:

{(x+1)(x+2)} / {(x+11)(x-2)} = 1

(x+1)(x+2) = (x+11)(x-2)

x^2 +2x +x +2 = x^2 + 11x - 2x - 22

x^2 + 3x +2 = x^2 + 9x -22

2+ 22 = 9x - 3x

24 = 6x

x = 4

Step-by-step explanation:

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