|x+1 x+2|
|x+2 x+3| find value of determinant
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x+1×x+3-x+2×x+2
= x(x+3)+1(x+3)- x(x+2)+2(x+2)
x²+3x+x+3 - x²-2x+2x+4
x²+4x+3- x²-4x+4
x²-x² +4x-4x +3-4
3-4
-1
answer the value of discriminant is -1
mark the answer surely as Brainliest
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Answer:
Step-by-step explanation:
D = (x+1)*(x+3)-(x+2)(x+2)
=x^2+4x+3-(x^2+4x+4)
=x^2+4x+3-x^2-4x-4
=3-4
= - 1
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