Math, asked by 0738374895, 11 months ago

|x+1 x+2|
|x+2 x+3| find value of determinant

Answers

Answered by Jk15
0

x+1×x+3-x+2×x+2

= x(x+3)+1(x+3)- x(x+2)+2(x+2)

x²+3x+x+3 - x²-2x+2x+4

x²+4x+3- x²-4x+4

x²-x² +4x-4x +3-4

3-4

-1

answer the value of discriminant is -1

mark the answer surely as Brainliest

Answered by haseebzarmina
0

Answer:

Step-by-step explanation:

D = (x+1)*(x+3)-(x+2)(x+2)

=x^2+4x+3-(x^2+4x+4)

=x^2+4x+3-x^2-4x-4

=3-4

= - 1

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