Math, asked by surendrakumar95, 9 months ago

(x+1)(x+2)(x+3)(x+3)(x+4)-8=0​

Answers

Answered by nikhillathwalpanipat
0
X^5 +5 is the answer I thought
Answered by aparnabhadoria
37

Answer:

  • (x+1)(x+2)(x+3)(x+3)(x+4)-8=0
  • (x+1)(x+2)(x+3)(x+3)(x+4)-8=05x+13-8=0
  • (x+1)(x+2)(x+3)(x+3)(x+4)-8=05x+13-8=05x+5=0
  • (x+1)(x+2)(x+3)(x+3)(x+4)-8=05x+13-8=05x+5=05x=5
  • (x+1)(x+2)(x+3)(x+3)(x+4)-8=05x+13-8=05x+5=05x=50

I hope my answer was helpful ☺️

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