Question

(x+1)(x+2)(x+3)(x+4)+1 factorization​

Answer 1

Hi mate

Here is ur answer ✏

$\huge\sf\bold{\pink{Given}}</p><p>$

$\sf(x + 1)(x + 2)(x + 3)(x + 4) + 1$

$\huge\sf\bold{\pink{Answer}}$

$\sf(x + 1)(x + 2)(x + 3)(x + 4) + 1$

$\sf = ( {x}^{2} + 5x + 4).( {x}^{2} + 5x + 6) + 1$

$\sf = ( {x}^{2} + 5x + 5)^{2} - 1 + 1$

$\sf = ( {x}^{2} + 5x + 5)^{2}$

$\sf( {x}^{2} + 5x + 5).( {x}^{2} + 5x + 5)$

$\sf = {(x}^{2} + 5x )$