Math, asked by ROHIT1818RJ, 10 months ago

x-1/x-2+x;_3/x-4=10/3​

Answers

Answered by dp14380dinesh
0

Answer:

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Attachments:
Answered by sare83
1

Answer:

2x^2-15x+25=0

Step-by-step explanation:

Given that,

x-1/x-2 + x-3/x-4 =10/3

((x-1)(x-4)+(x-3)(x-2))/(x-2)(x-4)=10/3

=>(x^2-x-4x+4+x^2-3x-2x+6)/x^2-4x-2x+8 =10/3

=>3(2x^2+10-10x)=10(x^2-6x+8)

=>6x^2-30x+30=10x^2-60x+80

=>10x^2-6x^2-60x+30x+80-30=0

=>4x^2–30x+50=0

=>2x^2-15x+25=0

therefore,

the value of x-1/x-2 + x-3/x-4=10/3 is 2x^2-15x+25=0

Hope this would be helpful for you

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