x-1/x-2+x;_3/x-4=10/3
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Answer:
2x^2-15x+25=0
Step-by-step explanation:
Given that,
x-1/x-2 + x-3/x-4 =10/3
((x-1)(x-4)+(x-3)(x-2))/(x-2)(x-4)=10/3
=>(x^2-x-4x+4+x^2-3x-2x+6)/x^2-4x-2x+8 =10/3
=>3(2x^2+10-10x)=10(x^2-6x+8)
=>6x^2-30x+30=10x^2-60x+80
=>10x^2-6x^2-60x+30x+80-30=0
=>4x^2–30x+50=0
=>2x^2-15x+25=0
therefore,
the value of x-1/x-2 + x-3/x-4=10/3 is 2x^2-15x+25=0
Hope this would be helpful for you
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