(x+1)(x+2)(x+3)(x+4)
Light1729:
just expansion?
uhh...we need to find the value of x and with expansion it would be a whole bigger peob
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(x+1)(x+2)(x+3)(x+4)
=(x^2+3x+2)(x^2+7x+12)
=x^4+10x^3+45x^2+64x+24
=(x^2+3x+2)(x^2+7x+12)
=x^4+10x^3+45x^2+64x+24
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