Question

x-1/x-2+x-3/x-4=3 1/3 ( solve by factorisation )

Answer 1

The factors are (x - 5)(2x - 5).

Step-by-step explanation:

The expression is:

$\frac{x-1}{x-2}+\frac{x-3}{x-4}=3\frac{1}{3}$

Simplify the expression as follows:

$\frac{x-1}{x-2}+\frac{x-3}{x-4}=3\frac{1}{3}$

$\frac{(x-1)(x-4)+(x-3)(x-2)}{(x-2)(x-4)}=\frac{10}{3}$

$\frac{x^{2}-5x+4+x^{2}-5x+6}{x^{2}-6x+8}=\frac{10}{3}$

$3(2x^{2}-10x+10)=10(x^{2}-6x+8)\\6x^{2}-30x+30=10x^{2}-60x+80\\4x^{2}-30x+50=0\\2x^{2}-15x+25=0$

Factorize the last expression by splitting the middle term as follows:

$2x^{2}-15x+25=0\\2x^{2}-10x-5x+25=0\\2x(x-5)-5(x-5)=0\\(x-5)(2x-5)=0$

Thus, the factors are (x - 5)(2x - 5).

Learn more:

https://brainly.in/question/4302805

Answer 2

Answer:

I hope it will you.

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Answer 3

Answer:

I hope it will you.

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