x-1 , x+2 , x-7 are in arithmetic progression find the value of x
please help me please
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Answered by
2
Answer:
Step-by-step explanation:
X-1, x+2 , x-7 and in AP
Common difference (d) in and AP is same.
So,
common difference = 2nd term - 1st term
= X+ 2 -(x-1) ........1
Common difference = 3rd term - 2nd term
= x-7 -(x+ 2)........2
As common difference is same, we can equate 1 and 2
X+ 2-(x-1) = x-7 -(x+ 2)
x + 2 -x + 1 = x-7 -x-2
3 = -9
This is not possible .
I think your question is wrong . The reason is shown above.
Plz cross check your question.
n8100020:
i think ur question is wrong
Answered by
1
hi, here is ur answer
if x-1,x+2,x-7 are in arithmetic progression
(x+2)-(x-1)=(x-7)-(x+2)
x+2-x+1=x-7-x-2
3=-9
therefore there is no value for x
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