Math, asked by kanha70, 1 year ago

x-1 , x+2 , x-7 are in arithmetic progression find the value of x
please help me please

Answers

Answered by Shalmali040203
2

Answer:

Step-by-step explanation:

X-1, x+2 , x-7 and in AP

Common difference (d) in and AP is same.

So,

common difference = 2nd term - 1st term

= X+ 2 -(x-1) ........1

Common difference = 3rd term - 2nd term

= x-7 -(x+ 2)........2

As common difference is same, we can equate 1 and 2

X+ 2-(x-1) = x-7 -(x+ 2)

x + 2 -x + 1 = x-7 -x-2

3 = -9

This is not possible .

I think your question is wrong . The reason is shown above.

Plz cross check your question.


n8100020: i think ur question is wrong
n8100020: sry i thought i typed in my inbox
kanha70: formula is 2b = a+c
kanha70: try
Answered by n8100020
1

hi, here is ur answer

if x-1,x+2,x-7 are in arithmetic progression

(x+2)-(x-1)=(x-7)-(x+2)

x+2-x+1=x-7-x-2

3=-9

therefore there is no value for x


n8100020: i think the question is wrong
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