x+1/x=3 find x^3+1/x^3
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Given x+1/x = 3
Required= x^3 + 1/x^3
we know that.
(x+1/x)^3 = (x)^3 + (1/x)^3 + 3×x×1/x(x + 1/x)
(x+1/x)^3 = (x)^3 + (1/x)^3 + 3(x+1/x)
(x+1/x)^3 - 3(x+1/x) = (x)^3 + (1/x)^3
substituting info
(3)^3 - 3(3) = (x)^3 + (1/x)^3
27 - 9 = (x)^3 + (1/x)^3
18 = (x)^3 + (1/x)^3
Required= x^3 + 1/x^3
we know that.
(x+1/x)^3 = (x)^3 + (1/x)^3 + 3×x×1/x(x + 1/x)
(x+1/x)^3 = (x)^3 + (1/x)^3 + 3(x+1/x)
(x+1/x)^3 - 3(x+1/x) = (x)^3 + (1/x)^3
substituting info
(3)^3 - 3(3) = (x)^3 + (1/x)^3
27 - 9 = (x)^3 + (1/x)^3
18 = (x)^3 + (1/x)^3
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