Question

x-1,x-4,x-7 are in A P then find x​

Answer 1

Answer:

x-1,x-4,x-7 are in A P for any real value of x .

Step-by-step explanation:

A sequence of numbers are in AP, if the consecutive numbers have a fixed common difference .

For example - 3 , 5 , 7 , 9 ......    are in AP as the consecutive numbers have a fixed common difference 2 .

In this question , x-1,x-4,x-7 are in A P

So, the common difference ,d = x-4 -(x-1)

                                                 =  x -4 -x + 1

                                                 =  -3

Also, the common difference ,d = x-7 -(x-4)

                                                    =  x - 7 -x + 4

                                                     =  -3

The common difference is equal in both case so, any value of x could be possible so that x-1,x-4,x-7 are in A P .

Thus, x-1,x-4,x-7 are in A P for any real value of x .