x+1/x=7 find the value of x^3+1/x^3
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Answered by
1
x^2 + 1/x^2 + 2 = 49
x ^3 + 1/x^3 + 3(x+1/x) = 343
x^3 + 1 /x ^3 = 343 - 21
= 322
x ^3 + 1/x^3 + 3(x+1/x) = 343
x^3 + 1 /x ^3 = 343 - 21
= 322
Answered by
1
x+1/x=7
=x+1=7x
7x-x=1
6x=1
x=1/6
∵x=1/6
∴x^3+1/x^3
=(1/6)^4/(1/6)^3
=(1/6)^4/(1/6)^3
=(1/6)^4/1/216
=(1/6)^864
=864/6
=216
=x+1=7x
7x-x=1
6x=1
x=1/6
∵x=1/6
∴x^3+1/x^3
=(1/6)^4/(1/6)^3
=(1/6)^4/(1/6)^3
=(1/6)^4/1/216
=(1/6)^864
=864/6
=216
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