x - 1/x=7, then evaluate x^2-1/x^2
tejasri2:
i think there is a mistake in question plz check it out bro
Answers
Answered by
3
Hey
Here is ur answer
x -1/x =7
Now we know that (x-1/x)2 = x2 -1/x2 -2*x*1/x so (x-1/x)^2 +2 = x2 -1/x2
x2-1/x2 = (x-1/x)2 +2
x2-1/x2 = 7^2+2 =49 +2 =51
Hope it help u
Plz mark as brainliest(
Here is ur answer
x -1/x =7
Now we know that (x-1/x)2 = x2 -1/x2 -2*x*1/x so (x-1/x)^2 +2 = x2 -1/x2
x2-1/x2 = (x-1/x)2 +2
x2-1/x2 = 7^2+2 =49 +2 =51
Hope it help u
Plz mark as brainliest(
the identity (a-b)²
plz google it
and say the identity plz
the identity is (a-b)² = a²+b²-2ab
not a²-b²-2ab
check it out
ok......?
samje hoo
Answered by
3
Here is your answer
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If x -1/x =7 [ °•°Given ]
Then evaluate x²-1/x²
~~~~~~~~~~~~~~~~~~~
squaring on both sides
__________________
=> x² -1 /x ² = 7²
=>x² -2. x .1/x + 1/x² = 49
=>x²-1/x²=49+2
=>x² -1/x²= 51
•°•Your answer is 51
------------------------------
If x -1/x =7 [ °•°Given ]
Then evaluate x²-1/x²
~~~~~~~~~~~~~~~~~~~
squaring on both sides
__________________
=> x² -1 /x ² = 7²
=>x² -2. x .1/x + 1/x² = 49
=>x²-1/x²=49+2
=>x² -1/x²= 51
•°•Your answer is 51
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