(x-1/x)(x+1/x) (x^2+1/x^2)(x^4+1/x^4)
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Answer:
x⁸-1/x⁸
Step-by-step explanation:
Firstly we have to use the identity (a+b)(a-b) =a²- b² in all cases .
So, It'll be :
= [x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]
= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]
= [(x²)²- (1/x²)²][x⁴+1/x⁴]
= [x⁴- 1/x⁴][x+1/x⁴]
= (x⁴)² - (1/x⁴)²
= x⁸-1/x⁸
You'll get your answer as : x⁸-1/x⁸
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