Question

x+1/x)( x-1/x)(x^2+1/x^2)(x^4+1/x^4)​

Answer 1

Answer:

using the identity (a+b)(a-b) =a²- b² in all cases

   [x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸

hope it would be helpful