Math, asked by maulikji60, 9 months ago

(x+1/x)(x-1/x)(x²+1/x²)(x⁴+1/x⁴)​

Answers

Answered by dilbagmavi8
2

have a look at attachment please

hope this helps you

Attachments:
Answered by Anonymous
1

[x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸

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