Question

(x+1/x)(x-1/x)(x²+1/x²)(x⁴+1/x⁴)​

Answer 1

have a look at attachment please

hope this helps you

Answer 2

[x+1/x][x-1/x][x²+1/x²][x⁴+1/x⁴]

= [x²- 1/x²][x²+1/x²][x⁴+1/x⁴]

=[(x²)²- (1/x²)²][x⁴+1/x⁴]

=[x⁴- 1/x⁴][x+1/x⁴]

=(x⁴)² - (1/x⁴)²

=x⁸-1/x⁸