Question

(x-1/xy)^3 factorize it using identities?

Answer 1

(x -1/xy)(x-1/xy)(x-1/xy)

Answer 2

${(x - y)}^{3} = {x}^{3} - 3 {x}^{2} y + 3 x {y}^{2} - {y}^{3} \\ {(xy)}^{3} = {x}^{3} {y}^{3} \\ {(x - 1)}^{3} = {x}^{3} - 3 {x}^{2} + 3x - 1 \\ {( \frac{(x - 1)}{xy} )}^{3} = \frac{ {x}^{3} - 3 {x}^{2} + 3x - 1 }{ {x}^{3} {y}^{3} } \\ hope \: it \: helps \\ please \: mark \: as \: brainliest$